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popupMenu: Make the section invisible if it has no visible children

Browse source 
https://bugzilla.gnome.org/show_bug.cgi?id=706852
This commit is contained in:
Jasper St. Pierre 2013-08-26 15:21:45 -04:00
parent f0da08bbb1
commit 5a0ac6c2ac
1 changed files with 11 additions and 2 deletions
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13
js/ui/popupMenu.js
View file

@ -921,10 +921,19 @@ const PopupMenuSection = new Lang.Class({
this.isOpen = true;
},
_syncVisibility: function() {
this.actor.visible = !this.isEmpty();
},
// deliberately ignore any attempt to open() or close(), but emit the
// corresponding signal so children can still pick it up
open: function() { this.emit('open-state-changed', true); },
close: function() { this.emit('open-state-changed', false); },
open: function() {
this._syncVisibility();
this.emit('open-state-changed', true);
},
close: function() {
this.emit('open-state-changed', false);
},
});
const PopupSubMenuMenuItem = new Lang.Class({